我正在编写一些CRUD应用程序的代码，该页面显示数据库表中的数据，并且应该与两个非常相似的表连接（由于历史原因或时间太长，这两个非常相似的表无法优化为一个表）。我确实使用switch语句和Java 8函数进行了优化，但是Intellij IDEA在两个不知道如何解决它的switch语句之间给了我重复代码片段警告。

我不是要优化设计，而是重构重复的代码片段并修复此警告。

我有一种search方法，用于从数据库中搜索数据，并通过TaxCustomerType枚举使用来自不同表的单独逻辑：

    public PageUtils<IndividualTaxactorVO> search(TaxCustomerType type,IndividualTaxactorQuery query,UserDO principal) {
        //... ignore for conciseness
        Function<actorCondition,Integer> counter;
        Function<actorCondition,Collection<IndividualTaxactorVO>> searcher;
        switch (type) {
            case INDIVIDUAL: {
                counter = individualTaxactordao::countIndividual;
                searcher = individualTaxactordao::searchIndividual;
                break;
            }
            case CORPORATE: {
                counter = individualTaxactordao::countCorporate;
                searcher = individualTaxactordao::searchCorporate;
                break;
            }
            default:
                throw new RuntimeException("不能识别的个税客户类型：" + type);
        }
        int total = counter.apply(condition);
        if (total == 0) {
            return PageUtils.empty();
        }
        Collection<IndividualTaxactorVO> list = searcher.apply(condition);
        return new PageUtils<>(list,total);
    }

我还有一个link方法可以插入表中并进行一些检查，也可以使用TaxCustomerType枚举使用单独的逻辑：

    public void link(TaxCustomerType type,String customerId,UserDO principal) {
        Function<String,IdAndTaxCodeAndDisabledOnly> findById;
        BiFunction<String,String,Integer> existsCounter;
        switch (type){
            case INDIVIDUAL: {
                findById = individualCustomerService::findTaxCodeAndDisabledById;
                existsCounter = individualTaxactordao::countCorporateByCompanyIdAndTaxCode;
                break;
            }
            case CORPORATE: {
                findById = customerService::findTaxCodeAndDisabledById;
                existsCounter = individualTaxactordao::countIndividualByCompanyIdAndTaxCode;
                break;
            }
            default:
                throw new RuntimeException("不能识别的个税客户类型：" + type);
        }
        IdAndTaxCodeAndDisabledOnly customer = findById.apply(customerId);
        if (customer == null) {
            throw new ApplicationRuntimeException(HttpStatus.NOT_FOUND,"客户不存在");
        }
        if(customer.isDisabled()){
            throw new ApplicationRuntimeException(HttpStatus.FAILED_DEPENDENCY,"客户已禁用");
        }
        int exists=existsCounter.apply(principal.getcompanyid(),customerId);
        if(exists>0){
            throw new ApplicationRuntimeException(HttpStatus.CONFLICT,"已是智能个税客户，不可重复添加。");
        }
        // insert into table ... ignore for conciseness
    }

绝对重复的代码片段行是：

在search方法中：

        switch (type) {
            case INDIVIDUAL: {
                counter = individualTaxactordao::countIndividual;
                searcher = individualTaxactordao::searchIndividual;
                break;
            }
            case CORPORATE: {
                counter = individualTaxactordao::countCorporate;
                searcher = individualTaxactordao::searchCorporate;
                break;
            }
            default:
                throw new RuntimeException("不能识别的个税客户类型：" + type);
        }

并使用link方法：

        switch (type){
            case INDIVIDUAL: {
                findById = individualCustomerService::findTaxCodeAndDisabledById;
                existsCounter = individualTaxactordao::countCorporateByCompanyIdAndTaxCode;
                break;
            }
            case CORPORATE: {
                findById = customerService::findTaxCodeAndDisabledById;
                existsCounter = individualTaxactordao::countIndividualByCompanyIdAndTaxCode;
                break;
            }
            default:
                throw new RuntimeException("不能识别的个税客户类型：" + type);
        }

我认为这两个代码段具有绝对不同的逻辑，但具有相同的switch模式，我无法忍受IDE警告，请帮助我修复它。