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将json转换为对象php

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我刚学过php

我有一个单独的数据库表，我想将该表与仅1个参数结合使用以JSON输出，但是结果输出是错误的，如何将我的JSON更改为正确且易于使用的JSON。

谢谢

json输出：

[
 [
    {
        "id_service": "3","reference_number": "","tracking_number": "RJC-0000-0001","kd_inbound": "INB-1000-0001","tgl_inbound": "2019-11-07 00:00:00","status_inb": "1"
    }
 ],[
    {
        "id_service": "3","kd_outbag": "BAG-1468-0002","tanggal_outbag": "2019-11-07 00:00:00","status_outbag": "1"
    }
 ],"kd_outbound": "OTB-1826-0001","tgl_outbound": "2019-11-07 17:04:49","status_otb": "1"
    }
 ],]

这是我的代码

 public function awb_get() {
    $id = $this->get('tracking_number');
    $res= array(      
      $this->M_tarif->tampil_status_inbound($id),$this->M_tarif->tampil_status_otboundbag($id),$this->M_tarif->tampil_status_otboundori($id),$this->M_tarif->tampil_status_indes($id),$this->M_tarif->tampil_status_outdes($id),$this->M_tarif->tampil_status_runsheet($id),$this->M_tarif->tampil_db_service_status($id)
    );
    $this->response($res,200);
}

我想要这样

{
"status": 200,"error": false,"awb": [
    {
        "tracking_number": "RJC-0000-0004","status": "order","tanggal": "2019-10-30"
    },{
        "tracking_number": "RJC-0000-0004","status": "Inbound to origin","tanggal": "2019-11-03"
    }
]
}
liufangxin 回答：将json转换为对象php

您的json响应不正确。 因此，首先您必须先重置JSON，然后再发送至函数。我曾作为示例重新排列JSON并将其转换为stdClass对象。请检查下面的代码以转换为您的回复。

$arr ='[
 [
    {
        "id_service": "3","reference_number": "","tracking_number": "RJC-0000-0001","kd_inbound": "INB-1000-0001","tgl_inbound": "2019-11-07 00:00:00","status_inb": "1"
    }
 ],[
    {
        "id_service": "3","kd_outbag": "BAG-1468-0002","tanggal_outbag": "2019-11-07 00:00:00","status_outbag": "1"
    }
 ],"kd_outbound": "OTB-1826-0001","tgl_outbound": "2019-11-07 17:04:49","status_otb": "1"
    }
 ],]';

$result = str_replace(array('[',']','\n'),'',htmlspecialchars(json_encode($arr),ENT_NOQUOTES));
$str = preg_replace('/\\\"/',"\"",$result);

$json = '[';
$json .= substr($str,2,-1); // Substring -1 character from the end of the json variable,this will be the trailing comma. 
$json .= ']';
$jsonData = preg_replace("/,(?!.*,)/","",$json);

echo "<pre>";
print_r(json_decode($jsonData));
echo "</pre>";

输出：

Array
(
    [0] => stdClass Object
        (
            [id_service] => 3
            [reference_number] => 
            [tracking_number] => RJC-0000-0001
            [kd_inbound] => INB-1000-0001
            [tgl_inbound] => 2019-11-07 00:00:00
            [status_inb] => 1
        )

    [1] => stdClass Object
        (
            [id_service] => 3
            [reference_number] => 
            [kd_outbag] => BAG-1468-0002
            [tanggal_outbag] => 2019-11-07 00:00:00
            [status_outbag] => 1
        )

    [2] => stdClass Object
        (
            [id_service] => 3
            [reference_number] => 
            [kd_outbound] => OTB-1826-0001
            [tgl_outbound] => 2019-11-07 17:04:49
            [status_otb] => 1
        )

)
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