如果节点值是某个值,我想重命名节点并将其上移一个级别。
到目前为止,我写了这篇文章:
awk '{if(index($4""$5,"*") != 0){print}}' file
输入:
import datetime
from datetime import date
date1 = '2019-01-01'
date2 = '2019-01-30'
start = datetime.datetime.strptime(date1,'%Y-%m-%d')
end = datetime.datetime.strptime(date2,'%Y-%m-%d')
step = datetime.timedelta(days=1)
while start <= end:
daterange = print(start.strftime('%Y%m%d'))
start += step
type(daterange)
输出:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="stock/images/image[main_image = 1]">
<primary>
<xsl:apply-templates />
</primary>
</xsl:template>
</xsl:stylesheet>
这几乎很好,但是我想将<root>
<stock>
<code>Apple</code>
<images>
<image>
<img_file>1.jpg</img_file>
<main_image>1</main_image>
</image>
<image>
<img_file>2.jpg</img_file>
<main_image>0</main_image>
</image>
</images>
</stock>
</root>
节点上移一层,位于<root>
<stock>
<code>Apple</code>
<images>
<primary>
<img_file>1.jpg</img_file>
<main_image>1</main_image>
</primary>
<image>
<img_file>2.jpg</img_file>
<main_image>0</main_image>
</image>
</images>
</stock>
</root>
之外,例如:
<primary>