我正在运行这个简单的应用程序，以在GTX1080ti GPU上执行图像调整大小：

#include <opencv2/opencv.hpp>
#include "opencv2/cudaimgproc.hpp"
#include "opencv2/cudawarping.hpp"
using namespace std;
using namespace cv;
using namespace cv::cuda;
static void gpuResize(Mat in,Mat out){
    double k = in.cols/416.;
    cuda::GpuMat gpuInImage;
    cuda::GpuMat gpuOutImage;
    gpuInImage.upload(in);
    const Size2i &newSize = Size(416,in.rows / k);
    cout << "newSize " << newSize<< endl;
    cuda::resize(gpuInImage,gpuOutImage,newSize);
    gpuOutImage.download(out);
}

int main(){
    Mat im = Mat::zeros(Size(832,832),CV_8UC3);
    Mat out;
    if (getcudaEnabledDeviceCount() == 0){
        return cerr << "No GPU found or the library is compiled without CUDA support" << endl,-1;
    }
    cv::cuda::printShortCudaDeviceInfo(cv::cuda::getDevice());
    gpuResize(im,out);
    cout << "real size="<<out.size() <<endl;
}

我得到的输出：

Device 0:  "GeForce GTX 1080 Ti"  11177Mb,sm_61,Driver/Runtime ver.10.10/10.10
newSize [416 x 416]
real size=[0 x 0]

为什么输出矩阵的大小为0x0，我该如何解决？