您不能以编程方式提交用户响应(引发“抱歉,此响应已提交。”异常)。 Submit()[1]函数用于尚未提交的响应(以编程方式进行)。
但是,您可以为目标Spreadsheet [2] [3](链接到表单的表单)创建一个on form提交触发器,并从表单中获取标题以将其插入所需的列中(我使用了第七栏):
function onUserFormSubmit(e) {
//Get Form from formID and title
var form = FormApp.openById("[FORM-ID]");
var title = form.getTitle();
//Row where user response is inserted
var responseRow = e.range.getRow();
//Column where you want the title to be
var titleColumn = 7;
//Get responses sheet and insert the title in the given cell
var sheet = SpreadsheetApp.openById("[SPREADSHEET-ID]");
sheet.getSheetByName("Form responses 1").getRange(responseRow,titleColumn).setValue(title);
}
function createTrigger() {
var sheet = SpreadsheetApp.openById("[SPREADSHEET-ID]");
ScriptApp.newTrigger("onUserFormSubmit")
.forSpreadsheet(sheet)
.onFormSubmit()
.create();
}
[1] https://developers.google.com/apps-script/reference/forms/form-response#submit()
[2] https://developers.google.com/apps-script/guides/triggers/installable
[3] https://developers.google.com/apps-script/guides/triggers/events#google_sheets_events
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