我有此链接中所述的相同问题（但很快） Getting common data from two different types of array
我尝试过：
val list=ArrayList<Model>()
val list1=ArrayList<Model1>()
val hashMap=Hashmap<Int,Int>()
for (i in list.indices) {
val data = list1.filter { it.name == list[i].name }
if (data.isnotEmpty()) {
hashMap.put(data[0].id,list[i].id)
}
}
您可以使用intersect来检索两个列表之间的共同项目：
val l1 = listOf<Int>(1,2,3,4,5,6,7,8,9)
val l2 = listOf<Int>(1,9)
println(l1.intersect(l2))
要做的就是定义两个项目之间的相等性：
class A(val name: String) {
override operator fun equals(other: Any?): Boolean {
if (other is B)
return this.name == other.anotherFieldForName
return false
}
}
class B(val anotherFieldForName: String)
val l1 = listOf<A>(A("Bob"),A("Alice"),A("Margoulin"))
val l2 = listOf<B>(B("Bob"),B("Margoulin"))
println(l1.intersect(l2))
println(l2.intersect(l1))
编辑：根据下面的评论，这是一种无需对谓词进行两次迭代的方法：
val map = list.mapNotNull{el ->
list1.firstOrNull{el1 -> el.name == el1.name}?.let{el1 -> el.id to el1.id}
}.toMap()