我试图不使用读取xml的旧方法,并尝试对xml进行linq,但是我很难完成以下任务:
响应XML
<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Body>
<PolicyResponse>
<serviceResponse>
<responseCode>0</responseCode>
<responseDescription>Success</responseDescription>
<responseDetail>Success</responseDetail>
<paging>
<pageNum>1</pageNum>
<pageSize>3</pageSize>
<totalRecords>3</totalRecords>
</paging>
</serviceResponse>
<detailsResponseList>
<detailResponse>
<policy>
<policySummaryInfo>
<PolicyNumber>1199128</PolicyNumber>
<PremiumChangeAmt>...</PremiumChangeAmt>
<WrittenAmt>...</WrittenAmt>
<PolicyStatusDesc>Expired</PolicyStatusDesc>
<BillingInfo>
<InsuredOrPrincipal>...</InsuredOrPrincipal>
</BillingInfo>
</policySummaryInfo>
</policy>
</detailResponse>
<detailResponse>
<policy>
<policySummaryInfo>
<PolicyNumber>1199128</PolicyNumber>
<PremiumChangeAmt>...</PremiumChangeAmt>
<WrittenAmt>...</WrittenAmt>
<PolicyStatusDesc>active</PolicyStatusDesc>
<BillingInfo>
<InsuredOrPrincipal>...</InsuredOrPrincipal>
</BillingInfo>
</policySummaryInfo>
</policy>
</detailResponse>
</detailsResponseList>
</PolicyResponse>
</out2:getPolicySummaryResponse>
</soapenv:Body>
</soapenv:Envelope>
我正在用C#进行
XDocument xdoc = new XDocument();
xdoc = XDocument.Parse(xmlResponse);
IEnumerable<XElement> items =
from el in xdoc.Descendants("detailResponse")
select el;
使用此代码,我可以读取bot detailReponse元素,但我要保留的是<PolicyStatusDesc></PolicyStatusDesc>
等于active的XML detailResponse结构。那可能吗。我设法根据元素名称来收集特定的数据,但是如何使用Linq to XML保持整个XML子元素结构(detailResponse元素及其子元素)。
谢谢