import cmath
import math
print(" we are going to programming second grade equation in python")
print(" a^2 x + b x + c =0")
num1 = int(input(" enter A please : "))
num2 = int(input(" enter B please : "))
num3 = int(input(" enter c please : "))
v = num2*num2 - 4 *num1 * num3
if v < 0:
print("wrong values")
else:
print("root of delta =",v)
k= math.sqrt(v)
def two_sol(x,y) :
x_f= (-y + v)/(4*x)
x_s =(-y - v)/(4*x)
return x_f,x_s
def one_sol(x):
x_f = (-y + v) / (4 * x)
if v >0 :
print("we have two solution :",two_sol(num1,num2))
elif v == 0:
print( "we have one solution :",one_sol(y))
else:
print(" there is no solution !!")
当我在代码中使用（0）作为num1方程时崩溃python
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问答
wkz123456 回答：当我在代码中使用（0）作为num1方程时崩溃python
当然，您有一个被零除的错误：num1-> x
def two_sol(x,y) :
x_f= (-y + v)/(4*x)
x_s =(-y - v)/(4*x)
和
def one_sol(x):
x_f = (-y + v) / (4 * x)
您需要检查x是否为零。如果x为零，则应该只有一个解。
希望有帮助。
,之所以发生这种情况，是因为我们无法将任何数字除以0，所以您不想做什么？ 如果需要，当x输入为0时将其替换为1，表示数字除以1，则代码为
def two_sol(x,y) :
if int(x) == 0: x = 1
x_f= (-y + v)/(4*x)
x_s =(-y - v)/(4*x)
return x_f,x_s
def one_sol(x):
if int(x) == 0: x = 1
x_f = (-y + v) / (4 * x)
否则，如果x输入为0，则返回并且不再计算！代码将是
def two_sol(x,y) :
if int(x) == 0: return
x_f= (-y + v)/(4*x)
x_s =(-y - v)/(4*x)
return x_f,x_s
def one_sol(x):
if int(x) == 0: return
x_f = (-y + v) / (4 * x)