与其他答案类似，但我会写出一些不同之处：

people = [
    {'name': "Azura",'group': "cute_python"},{'name': "Mate",{'name': "Anna",'group': "fatal_error"},{'name': "John",'group': "fatal_error"}
]
name_to_group = {d['name']: d['group'] for d in people}

print("Group Information")
names = ','.join(name_to_group)
name = input(f"Enter one of {names} or 0 to exit: ")
while name != '0':
    if name not in name_to_group:
        continue
    print(f"{name} is in group {name_to_group[name]}")
    name = input(f"Enter one of {names} or 0 to exit: ")
print('Good Bye')

示例输出：

Group Information
Enter one of Azura,Mate,Anna,John or 0 to exit: Mate
Mate is in group cute_python
Enter one of Azura,John or 0 to exit: John
John is in group fatal_error
Enter one of Azura,John or 0 to exit: 0
Good Bye

尝试一下：

people = [
    {'name': "Azura",'group': "fatal_error"}
]

def op(names):
    for value in people:
        if value['name'].lower() in names.lower():
            print(value['group'])

x = op(input("Welcome to the py-group-information,I can tell you where 
    those users belong to : Azura Mate  Anna   John Which user do you want 
    to ask for ?"))

以下是从您的数据结构中提取的核心逻辑（有意省略列表和欢迎屏幕文本）。假设您有这些，请首先捕获以下用户输入，然后继续搜索他们所属的组。

user_name = input("Which user do you want to ask for ?")
    for item in people:
        for key in item:
            if item[key] == user_name:
                    print(item['group'])
                    break