如何从以下输出中仅打印第二个元素?
"java.exe","7184","RDP-Tcp#20","2","231,440 K","Running","CAB\27","0:00:59","start-app"
所以基本上我只想得到“ 7184”
这是我正在使用的脚本:
@ECHO OFF
echo Stoping the Application ...
echo.
tasklist /v /fo csv | findstr /i "start-app"
谢谢