就像标题中所说的，如何找到将列表分为三个列表的所有方式？例如1,2,3将返回
[1,3]
[1] [2] [3]
[1,2] [3] [ ]
[1] [2,3] [ ]
[1,3] [2] [ ]
我尝试了很多东西，但似乎无法理解。谢谢！
huangyanglv 回答：找到所有方法来决定列表成三
您可以从库combinations中使用itertools
import itertools
my_list = [1,2,3]
for i in range(len(my_list)):
print(list(itertools.combinations(my_list,i + 1)))
输出
[(1,),(2,(3,)]
[(1,2),(1,3),3)]
[(1,3)]
现在您可以添加每个列表的长度，并添加缺少的空列表（以完成3个列表），瞧-您得到的结果
,这是一个可能的解决方案：
import itertools
# your input data list
a = [1,3]
# util function to convert list of tuples to list of list
f = lambda x: [list(i) if isinstance(i,tuple) else i for i in x]
# list1 is all combinations of sublists having length = 1,..length_of_a from input list `a` and empty list []
list1 = []
for i in range(1,len(a)+1):
list1.extend(itertools.combinations(a,i))
list1.extend([()]*(len(a)-1))
# list2 is all combinations of sublists having length = length_of_a from the list1
list2 = list(set(itertools.combinations(list1,len(a))))
# filtering out and converting list of tuples for the final results
results = [f(i) for i in list2 if sum(itertools.chain(*i)) == sum(a) and set(itertools.chain(*i)) == set(a)]
results.append(a)
# print out the results
for r in results:
print(r)
输出：
[[1、2、3]，[]，[]]
[[3]，[1、2]，[]]
[[1]，[2]，[3]]
[[2]，[1、3]，[]]
[[1]，[2、3]，[]]
[1、2、3]