ggplot2,x轴无法正确显示刻度

我正在为我的海报创建一个barplot,但是遇到了问题。 我的x轴上有一个因子,而我的y轴上有一个数字。我希望我的x轴显示因子的每个级别,但名称不同。

为此,我使用了scale_x_discrete命令,该命令应该允许我执行此操作。但是,它只是删除所有刻度。请在下面找到重现该问题所需的所有代码。

F_Value <- c(13.011,8.827,15.586,7.223,16.190,9.844)
Pathway <- as.factor(1:6)
Transformation <- as.factor(c(1,1,2,3,3))
Outlier <- as.factor(c("Outliers","Outlier Removed","Outliers","Outlier Removed"))
df <- as.data.frame(cbind(F_Value,Pathway,Transformation,Outlier))
df


ggplot(df,aes(x = Pathway,y = F_Value,f
           ill = factor(Outlier))) + 
  geom_bar(stat = "identity",position = "dodge") +
  scale_x_discrete(labels = c("1" = "Raw","2" = "Raw,Trimmed","3" = "Log","4" = "Log,"5" = "Normalised","6" = "Normalised,Trimmed")) +
  scale_fill_discrete(name = "Outliers",labels = c("Trimmed","Not Trimmed")) +
  xlab("Pathway") +
  ylab("F-Statistic") +
  ggtitle("F-Statistics by Pathway") +
  theme_light()
liyazhao 回答:ggplot2,x轴无法正确显示刻度

将x变量转换为字符:

ggplot(df,aes(x = as.character(Pathway),y = F_Value,f
           ill = factor(Outlier))) + 
  geom_bar(stat = "identity",position = "dodge") +
  scale_x_discrete(labels = c("1" = "Raw","2" = "Raw,Trimmed","3" = "Log","4" = "Log,"5" = "Normalised","6" = "Normalised,Trimmed")) +
  scale_fill_discrete(name = "Outliers",labels = c("Trimmed","Not Trimmed")) +
  xlab("Pathway") +
  ylab("F-Statistic") +
  ggtitle("F-Statistics by Pathway") +
  theme_light()
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