如何在DB2 10.5及更高版本中找到最早的活动事务?

由于snAPAPPL管理视图和snAP_GET_APPL表功能已弃用,因此在10.5版及更高版本中,如何通过其他方式找到最早的活动事务?

gordon000 回答:如何在DB2 10.5及更高版本中找到最早的活动事务?

您可以使用以下功能来获取过去不推荐使用的“快照”管理视图所提供的信息

MON_GET_TRANSACTION_LOG
MON_GET_UNIT_OF_WORK
MON_GET_DATABASE

查询如下:

select integer(mtl.applid_holding_oldest_xact)     as "Oldest Transaction",integer(muow.uow_log_space_used /1024 / 1024)  as "Log used(Mb)",integer(muow.num_locks_held)                   as "Locks Held",integer(muow.client_idle_wait_time)            as "Idle (seconds)",time(muow.uow_stop_time)                       as "UOW Stop Time",muow.rows_returned                             as "Rows Returned",muow.rows_read                                 as "Rows Read",integer(muow.rows_inserted)                    as "Rows Inserted",integer(muow.rows_updated)                     as "Rows Updated",integer(muow.rows_deleted)                     as "Rows Deleted"
from table(mon_get_transaction_log(-1)) mtl
     inner join
     table(mon_get_unit_of_work(null,-1)) muow
     on muow.member = mtl.member 
     and muow.application_handle = mtl.applid_holding_oldest_xact
,

正确!您可以使用MON_GET_TRANSACTION_LOG表函数。这是在Knowledgecenter(https://github.com/algolia/algolia-cli#examples)中找到的另一个查询:

Select MEMBER,CUR_COMMIT_DISK_LOG_READS,CURRENT_ACTIVE_LOG,APPLID_HOLDING_OLDEST_XACT from table(mon_get_transaction_log(-1)) as t
order by member asc

输出:

MEMBER  CUR_COMMIT_DISK_LOG_READS  CURRENT_ACTIVE_LOG  APPLID_HOLDING_OLDEST_XACT
------  -------------------------  ------------------  --------------------------
     0                       9999                   1                           7
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