Dim myList As New List(Of Integer)(New Integer() {1001,1006,1011,1016,1021,1026,1031,1036,1041,1046,1051,1056,1061,1066,1071})
如何减少上面的代码?
Dim myList As New List(Of Integer)(New Integer() {1001,1006,1011,1016,1021,1026,1031,1036,1041,1046,1051,1056,1061,1066,1071})
如何减少上面的代码?
第一个列表的初始化可以通过这种方式完成
Dim init As Integer = 1001
Dim myList As IEnumerable(Of Integer) = Enumerable.Range(start:=0,count:=15).
Select(Function(x) init + (x * 5))
字符串结果的创建可以通过String.Join
完成Dim result = String.Join(Environment.NewLine,myList)
Console.WriteLine(result)