喜欢这个。
infos = [[0,'virtual_94',{'sequence': 10,'display_type': False,'product_uom_qty': 1,'qty_delivered_manual': 0,'price_unit': 1000,'discount': 0,'customer_lead': 0,'product_id': 1,'product_no_variant_attribute_value_ids': [[6,False,[]]],'name': 'Produto de teste','product_uom': 1,'analytic_tag_ids': [[6,'route_id': False,'tax_id': [[6,[1]]],'sale_line_exemption_id': False}]]
ID = infos[0][2]["tax_id"][0][2][0]
,
您可以使用其各自的索引访问列表,并使用其各自的键访问字典值。
以下是获得所需输出的明细:
#Access the third element (index 2) in your initial list to get a dictionary
d = your_list[2]
#Get value for key 'tax_id' : [[6,[**1**]]]
tax_id_list = d['tax_id']
# Get sublist: [6,[**1**]]
tax_id_sub_list = tax_id_list[0]
# Get list with one in it: [**1**]
element_with_one = tax_id_sub_list[2]
#Finally,access the first element in that list: 1
print(element_with_one[0])
输出:
1
将以上所有内容合并为一行(但是,较难阅读):
print(your_list[0][2]['tax_id'][0][2][0])
输出:
1
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