我有一个服务器针对CURL请求curl --insecure -i -F files=@test.png https://xxx.xx.xx.xxx/powerai-vision/api/dlapis/b06564c9-7c1e-4642-a5a6-490310563d49
返回以下内容。
HTTP/1.1 200 OK
Server: nginx/1.15.5
Date: Mon,04 Nov 2019 06:23:14 GMT
Content-Type: application/json
Content-Length: 3556
Connection: keep-alive
Vary: accept-Encoding
X-Powered-By: Servlet/3.1
access-control-allow-origin: *
access-Control-Allow-Headers: X-Auth-Token,origin,content-type,accept,authorization
access-Control-Allow-Credentials: true
access-Control-Allow-Methods: GET,POST,PUT,DELETE,OPTIONS,HEAD
Content-Language: en
X-Frame-Options: SAMEORIGIN
X-Content-Type-Options: nosniff
X-XSS-Protection: 1; mode=block
strict-transport-security: max-age=15724800; includeSubDomains
{"webAPIId":"b06564c9-7c1e-4642-a5a6-490310563d49","imageUrl":"http://powerai-vision-service:9080/powerai-vision-api/uploads/temp/b06564c9-7c1e-4642-a5a6-490310563d49/58c6eb6a-aaa4-4d6b-8c20-aadec4558107.png","imageMd5":"bd123739171d95d30d570b2cd0ed1aed","classified":[{"confidence":0.997600257396698,"ymax":997,"label":"white_box","xmax":1407,"xmin":1166,"ymin":760,"attr":[{}]},],"result":"success"}
我想使用node.js来构建一个Web应用程序来处理它并在最后获取json字符串。为此,我正在使用以下代码。
'use strict';
/* eslint-env node */
const express = require('express');
const request = require('request');
const MISSING_ENV =
'Missing required runtime environment variable POWERAI_VISION_WEB_API_URL';
require('dotenv').config({
silent: true,});
const app = express();
const port = process.env.PORT || process.env.VCAP_APP_PORT || 8081;
const poweraiVisionWebApiUrl = process.env.POWERAI_VISION_WEB_API_URL;
console.log('Web API URL: ' + poweraiVisionWebApiUrl);
if (!poweraiVisionWebApiUrl) {
console.log(MISSING_ENV);
}
app.use(express.static(__dirname));
app.use(express.json());
app.post('/uploadpic',function (req,result) {
if (!poweraiVisionWebApiUrl) {
console.log(MISSING_ENV);
result.send({ data: JSON.stringify({ error: MISSING_ENV }) });
} else {
req.pipe(request.post({
url: poweraiVisionWebApiUrl,agentOptions: {
rejectUnauthorized: false,}
},function (err,resp,body) {
if (err) {
console.log(err);
}
console.log('Check 22');
console.log(body);
// console.log(JSON.parse(body).webAPIId);
result.send({ data: body });
}));
}
});
app.listen(port,() => {
console.log(`Server starting on ${port}`);
});
我遇到的问题是我不知道如何访问正文中的元素(json强)。现在console.log(body)
打印出垃圾(https://github.com/IBM/powerai-vision-object-detection/issues/61)。在node.js中处理此字符串的正确方法是什么?
我是Node.js编程的新手。
当我打印响应的标题时,得到以下输出。
{
server: 'nginx/1.15.5',date: 'Tue,05 Nov 2019 02:47:37 GMT','content-type': 'application/json','transfer-encoding': 'chunked',connection: 'keep-alive',vary: 'accept-Encoding','x-powered-by': 'Servlet/3.1','access-control-allow-origin': '*','access-control-allow-headers': 'X-Auth-Token,authorization','access-control-allow-credentials': 'true','access-control-allow-methods': 'GET,HEAD','content-language': 'en','x-frame-options': 'SAMEORIGIN','x-content-type-options': 'nosniff','x-xss-protection': '1; mode=block','strict-transport-security': 'max-age=15724800; includeSubDomains','content-encoding': 'gzip'
}
看起来内容编码是gzip。为什么向外卷曲和node.js响应不同?我应该如何处理gzip内容?有链接吗?