只是想知道我应该坚持使用reduce进行映射吗？
代码很长。有没有一种方法可以使它看起来更整洁？
const items = [
{ Name: "one" },{ error: true,code: "INVALID 1" },{ Name: "two" },{ Name: "three" },code: "INVALID OTHER" },]
const filtered = items.reduce((acc,item) => {
if (item.error === true) {
if (!acc.errors) {
acc.errors = [];
}
acc.errors.push(item);
return acc;
}
if (!acc.items) {
acc.items = [];
}
acc.items.push(item);
return acc;
},{});
console.log(filtered)
是仅根据该对象是否包含error键确定它属于哪个对象？如果是这样，那该怎么办？
const items = [
{ Name: "one" },{ error: true,code: "INVALID 1" },{ Name: "two" },{ Name: "three" },code: "INVALID OTHER" },];
const filtered = {
errors: items.filter(i => Object.keys(i).includes('error')),items: items.filter(i => !Object.keys(i).includes('error'))
}
console.log(filtered);,
由于reducer的两个部分之间唯一的不同是您要按的键，因此请提取key选择，并使所有内容都取决于key：
const items = [{"Name":"one"},{"error":true,"code":"INVALID 1"},{"Name":"two"},{"Name":"three"},"code":"INVALID OTHER"}]
const filtered = items.reduce((acc,item) => {
const key = item.error ? 'errors' : 'items'
if (!acc[key]) acc[key] = []
acc[key].push(item)
return acc
},{})
console.log(filtered)