这里的Python新手试图解决我的nim代码游戏。 基本上，代码会删除1、2或3块石头，直到没有剩下为止。我正在尝试防止用户和AI进入负面状态（如果AI和用户之间只有一石之分，则用户应该不能移除两三块宝石。）到目前为止，这是我的代码：

import random
Stones = random.randint(15,30)
User = 0
YourTurn = True

print("This is a game where players take turns taking stones from a pile of stones. The player who 
takes the last stone loses.")
print("The current stone count is:",Stones)

while True:
     while YourTurn == True and Stones > 0:
    User = int(input("How many stones do you want to remove?"))
    if User == 1:
        Stones -= 1
        print("You removed 1 stone! The current stone count is:",Stones)
        YourTurn = not True            
    elif User == 2:
        Stones -= 2
        print("You removed 2 stone! The current stone count is:",Stones)    
        YourTurn = not True                       
    elif User == 3:
        Stones -= 3
        YourTurn = not True
        print("You removed 3 stone! The current stone count is:",Stones)
    else:
        print("You can only remove a maximum of 3 stones.")

    while YourTurn == False and Stones > 0:
        AI = random.randint(1,3)
        if AI == 1:
            Stones -= 1
            print("The A.I removed 1 stone! The current stone count is:",Stones)
            YourTurn = not False
        elif AI == 2:
            Stones -= 2
            print("The A.I removed 2 stone! The current stone count is:",Stones)
            YourTurn = not False
        elif AI == 3:
            Stones -= 3
            print("The A.I removed 3 stone! The current stone count is:",Stones)
            YourTurn = not False

if Stones <= 0:
    if YourTurn == True:
        print("The A.I took the last stone it lost. You won the game!")
        break
    elif YourTurn == False:
        print("You took the last stone you lost. The A.I won the game!")
        break

我不知道您如何使代码不陷入负面影响，我之前拥有的if和elif语句被代码忽略了。我将不胜感激。