我正在某种模式下在字符串中搜索作业。在测试代​​码时，我声明了一个默认值以便于测试。当我完成测试并尝试使用用户输入来运行代码时，输​​出将有所不同。 输出（使用默认值时）“在位置4处匹配”。但是当使用用户输入时，它会显示“ no match”。

这是我的代码：

int main() {
    char text[255],pattern[255];
    char sensitive = 'N';
    int n,a[255],i,j,k = 0,l,found = 0,t = 0,temp=0;
    printf("Enter a sentence,up to 255 characters:");
    fgets(text,255,stdin);
    text[strcspn(text,"\n")] = 0;
    printf("Enter a pattern,up to 255 characters:");
    fgets(pattern,stdin);
    pattern[strcspn(pattern,"\n")] = 0;
    printf("Should the match be case-sensitive,Y or N?");
    scanf("%c",&sensitive);

    if (sensitive == 'N' || sensitive == 'n') {
        for (i = 0; i < strlen(text); i++) {
            text[i] = tolower(text[i]);
            //printf("%c",text[i]);
        }
        for (i = 0; i < strlen(pattern); i++) {
            pattern[i] = tolower(pattern[i]);
            //printf("%c",pattern[i]);

        }
    }

    for (i = 0;text[i] != '\0';i++)
    {
        j = 0;
        if (text[i] == pattern[j] || pattern[j] == '.')
        {
            temp = i + 1;
            while (text[i] == pattern[j] || pattern[j] == '.')
            {
                i++;
                j++;
            }

            if (pattern[j] == '\0')
            {
                temp -= 1;
                printf("Matches at position %d\n",temp);
                exit(0);
            }
            else
            {
                i = temp;
                temp = 0;
            }
        }
    }

    if (temp == 0)
        printf("No match.\n");

    return 0;
}