我从CODE表中得到了一个列名，例如Projects_Table。如何使用linq选择所有这些列值。
我尝试过：
public ToolEntities db = new ToolEntities();
// GET: Projects_Table
public actionResult Index()
{
ViewBag.list = new SelectList(db.Projects_Table,"CODE","CODE");
return View(db.Projects_Table.ToList());
}
我想像从.cshtml页面中的下拉菜单一样填充此Viewbag.list。Linq不返回数据。
您可以像这样填充# never used Enumerator::Generator directly,but you called it out specifically
# in your question,and this seems to be doing the trick to get it working
enum = Enumerator::Generator.new do |y|
y.yield "ant"
y.yield "bear"
y.yield "cat"
end
p enum.reduce(&:+) # output: "antbearcat"
# crude example of modifying the strings as you join them
p enum.reduce('') { |memo,word| memo += word.upcase + ' ' }
# output: "ANT BEAR CAT "
而不是 String id = exchange.getRequest().getId();
exchange.getResponse().getHeaders().add("id",id);
SelectListItem您的视图SelectList这样
List<SelectListItem> projectTableList = new List<SelectListItem>();
foreach (var projectTable in db.Projects_Table)
{
projectTableList.Add(new SelectListItem
{
Text=projectTable.Code,Value=projectTable.ID.ToString()
});
}
ViewBag.list = projectTableList;
return View();