有人可以告诉我为什么数学不打印吗?

我正在编写一个代码,该代码在计算重量和里程后为用户提供其包裹的总数。它在工作之前就可以使用,但是在我进行了较小的更改之后,任何重量超过2磅的东西都无法打印出来。为什么会这样?

#include <stdio.h>
#include <stdlib.h>

int main(){
    int weight;
    int miles;
    double mileCost;
    int segment;
    int remainder;

    printf("Charge by weight:(We don't tale packages over 10lbs\n");
    printf("\n 1-2 lbs: $1.50\n 3-6 lbs: $3.70\n 7-10 lbs: $5.25\n ");
    printf("Enter your package's weight:\n");
    scanf("%d",&weight);


    printf("Charge by mile: \n");
    printf("$1.50 for every 500 miles\n");
    printf("Enter the total miles for your package:\n");
    scanf("%d",&miles);

    if(miles == 0 && weight == 0 && weight < 10){
        printf("Invalid entry! Try Again.");
    }

    segment= miles / 500;
    remainder = miles % 500;    
    if(remainder > 0)
        remainder = 1;

    if(weight <= 2){
        mileCost = 1.50 * (segment + remainder);
        printf("The charge for your package is: %f\n",mileCost);
    }
    if(weight > 2 && weight >= 6){
        mileCost = 3.70 * (segment + remainder);
        printf("The charge for your package is: %f\n",mileCost);
    }
    if(weight > 6 && weight >= 10){
        mileCost = 5.25 * (segment + remainder);
        printf("The charge for your package is: %f\n",mileCost);
    }
    return 0;
}
sunnygirl126 回答:有人可以告诉我为什么数学不打印吗?

您的上限写为大于或等于<=,而不是小于或等于if(weight > 2 && weight >= 6){ if(weight > 6 && weight >= 10){

if(weight > 2 && weight <= 6){
if(weight > 6 && weight <= 10){

应该是

{{1}}
,

关于:

if(weight > 2 && weight >= 6){

1)应该以{{1​​}}开头,因此如果体重

2)声明应为:

else

注意else if(weight > 2 && weight <= 6){

3)存在以下类似考虑因素:

<= 6
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