根据@Pascalo我们可以使用
fetch('https://commons.wikimedia.org/w/api.php?action=query&prop=revisions&rvslots=*&rvprop=content&format=json&titles=Data:France.map&origin=*')
从 Wikidata 获取 geojson 数据的完整 JS 解决方案如下:
class SPARQLQueryDispatcher {
constructor(endpoint) {
this.endpoint = endpoint;
}
query(sparqlQuery,simplify = true) {
const fullUrl = this.endpoint + "?query=" + encodeURIComponent(sparqlQuery);
const headers = {
Accept: "application/sparql-results+json"
};
return fetch(fullUrl,{
headers
})
.then(body => body.json())
.then(data => (simplify ? this.simplify(data) : data));
}
simplify(data) {
const bindings = data.results.bindings;
return bindings.map(binding => {
Object.keys(binding).forEach(function(key,index) {
binding[key] = binding[key].value;
});
return binding;
});
}
}
function buildQuery(ids) {
const wds = ids.map(id => `wd:${id}`).join(" ");
return `
SELECT ?item ?itemLabel ?geoshape ?geoshapeLabel
WHERE
{
VALUES ?item { ${wds} }
?item wdt:P3896 ?geoshape.
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
`;
}
function fetchGeojson(rows) {
const titles = rows
.filter(r => r.geoshape)
.map(r => r.geoshape.split("/data/main/").pop())
.join("|");
return fetch(`https://commons.wikimedia.org/w/api.php?action=query&prop=revisions&rvslots=*&rvprop=content&format=json&titles=${titles}&origin=*`)
.then(r => r.json())
.then(r => Object.values(r.query.pages))
.then(r => r.map(r => JSON.parse(r.revisions[0].slots.main["*"]).data));
}
const queryDispatcher = new SPARQLQueryDispatcher("https://query.wikidata.org/sparql");
const query = buildQuery(["Q90"]); // Q90 = Paris
queryDispatcher
.query(query)
.then(fetchGeojson)
.then(console.log);
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