我是整个 awk 工具的新手,对我来说似乎很复杂。
示例 ifconfig 输出:
enp2s0f1: flags=4099<UP,BROADCAST,MULTICAST> mtu 1500
ether xx:xx:xx:xx:xx:xx txqueuelen 1000 (Ethernet)
RX packets 0 bytes 0 (0.0 B)
RX errors 0 dropped 0 overruns 0 frame 0
TX packets 0 bytes 0 (0.0 B)
TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0
lo: flags=73<UP,LOOPBACK,RUNNING> mtu 65536
inet 127.0.0.1 netmask 255.0.0.0
inet6 ::1 prefixlen 128 scopeid 0x10<host>
loop txqueuelen 1000 (Local Loopback)
RX packets 338 bytes 27536 (26.8 KiB)
RX errors 0 dropped 0 overruns 0 frame 0
TX packets 338 bytes 27536 (26.8 KiB)
TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0
wlp3s0: flags=4163<UP,RUNNING,MULTICAST> mtu 1500
inet xxx.xxx.xxx.xxx netmask xxx.xxx.xxx.x broadcast xxx.xxx.xxx.xxx
inet6 xxxx::xxxx:xxxx:xxxx:xxxx prefixlen 64 scopeid 0x20<link>
ether xx:xx:xx:xx:xx:xx txqueuelen 1000 (Ethernet)
RX packets 143296 bytes 172270775 (164.2 MiB)
RX errors 0 dropped 5 overruns 0 frame 0
TX packets 32786 bytes 6774762 (6.4 MiB)
TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0
到目前为止,我得到了一个用于 ifconfig 过滤器的命令,它会丢弃环回以及其他不需要的东西。
ifconfig | awk 'BEGIN{ORS=RS="\n\n"} !/^lo/{print}' | awk '{print $1,$2}' | awk '!/^RX/{print}' | awk '!/^TX/{print}'
这是一个输出:
enp2s0f1: flags=4099<UP,MULTICAST>
ether xx:xx:xx:xx:xx:xx
wlp3s0: flags=4163<UP,MULTICAST>
inet xxx.xxx.xxx.xxx
inet6 xxxx::xxxx:xxxx:xxxx:xxxx
ether xx:xx:xx:xx:xx:xx
我研究了类似的问题,但我想知道如何使用 awk
从中间切线我已经尝试过这样的一行:
awk '!/flags=/{print}'
但它删除了包含 flags
所需的输出:
enp2s0f1:
ether xx:xx:xx:xx:xx:xx
wlp3s0:
inet xxx.xxx.xxx.xxx
ether xx:xx:xx:xx:xx:xx