使用 Python Turtle 图形和图章的平滑动画

是否可以使用 Turtle Graphics 和 stamp() 方法获得比以下代码更流畅的动画效果?

我曾尝试只使用 stamper.clearstamps(1) 内的 move_blocks 清除第一个图章,并且每次只绘制新块,但结果看起来相同。我认为问题可能出在后台调用 Screen.update(),尽管我还没有确认这一点。

import turtle


def move_blocks():
    stamper.clearstamps()
    new_block = blocks[-1].copy()
    new_block[0] += 20
    if new_block[0] > 250:
        new_block[0] = - 250
    blocks.append(new_block)
    blocks.pop(0)

    for block in blocks:
        stamper.goto(block[0],block[1])
        stamper.stamp()

    screen.update()
    turtle.ontimer(move_blocks,100)


screen = turtle.Screen()
screen.setup(500,500)
screen.tracer(0)  # Turn off automatic animation

stamper = turtle.Turtle("square")
stamper.penup()

blocks = [[0,0],[20,[40,[60,0]]

for block in blocks:
    stamper.goto(block[0],block[1])
    stamper.stamp()

move_blocks()
turtle.done()

非常感谢任何帮助。

gfhu20010 回答:使用 Python Turtle 图形和图章的平滑动画

我认为问题可能在于冲压调用 Screen.update() 背景,虽然我还没有证实这一点。

这似乎是真的,很容易确认,但不一定是整个问题。下面是我通过仅删除已失效的邮票 ID 来优化它的代码的返工,但它看起来并不比你的好。你可以看到我已经注释掉了 screen.update(),这没什么区别:

from turtle import Screen,Turtle

def move_blocks():
    new_block = blocks.pop(0)
    new_block[0] = blocks[-1][0] + 20

    if new_block[0] > 250:
        new_block[0] = -250

    blocks.append(new_block)

    stamper.goto(new_block)
    stamper.clearstamp(ids.pop(0))
    ids.append(stamper.stamp())

    # screen.update()
    screen.ontimer(move_blocks,100)

screen = Screen()
screen.setup(500,500)
screen.tracer(0)  # Turn off automatic animation

stamper = Turtle('square')
stamper.hideturtle()
stamper.penup()

blocks = [[0,0],[20,[40,[60,0]]
ids = []

for block in blocks:
    stamper.goto(block)
    ids.append(stamper.stamp())

# screen.update()

move_blocks()

screen.exitonclick()

为了聪明,我想对 drawingstamping 进行比较,但结果是一样的,填充操作触发了 screen.update()让我们回到起点:

from turtle import Screen,Turtle

CURSOR_SIZE = 20

def move_blocks():
    filler.clear()

    new_block = blocks.pop(0)
    new_block[0] = blocks[-1][0] + 20

    if new_block[0] > 250:
        new_block[0] = -250

    blocks.append(new_block)

    for block in blocks:
        fill(block)

    # screen.update()
    screen.ontimer(move_blocks,100)

def fill(position):
    filler.goto(position)

    filler.begin_fill()
    for _ in range(4):
        filler.forward(CURSOR_SIZE)
        filler.left(90)
    filler.end_fill()

screen = Screen()
screen.setup(500,500)
screen.tracer(0)  # Turn off automatic animation

filler = Turtle()
filler.hideturtle()
filler.penup()

blocks = [[0,0]]

for block in blocks:
    fill(block)

# screen.update()

move_blocks()

screen.exitonclick()

最后,我做了一个由 tracer() 和程序员发起的 screen.update() 调用控制的实现。我只是重塑光标并移动它以进行比较。这次将 screen.update() 注释掉后,您可以看到不同之处。

from turtle import Screen,Turtle

CURSOR_SIZE = 20
CURSOR_LENGTH = 80
STEP_SIZE = 1

def move():
    x = turtle.xcor() + STEP_SIZE

    if x - CURSOR_LENGTH/2 > 250:
        turtle.setx(-250 - CURSOR_LENGTH/2)
    else:
        turtle.forward(STEP_SIZE)

    screen.update()
    screen.ontimer(move,5 * STEP_SIZE)

screen = Screen()
screen.setup(500,500)
screen.tracer(0)  # Turn off automatic animation

turtle = Turtle()
turtle.shape('square')
turtle.shapesize(stretch_len=CURSOR_LENGTH/CURSOR_SIZE)
turtle.penup()

screen.update()

move()

screen.exitonclick()

然而,这个实现指出,早期的糟糕的视觉性能也是由于步长很大——如果你改变STEPSIZE = CURSOR_SIZE,那么你的步长和性能与你原来的一样.

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