我有一个数组
const newChecked = ["recreational","charity"]
和一个对象
const allactivities = [
{activity: '...',type: 'social',},{activity: '...',type: 'charity',type: 'recreational',]
而且我想获得一个新对象，该对象不包含 newChecked 中包含的类型。换句话说，newactivitiesList 应该包含 type 为 "social" 的数据。
const newactivitiesList = allactivities.filter((item) =>
newChecked.map((i) => {
return item.type !== i;
})
);
您可以将 Array#filter 与 Array#includes 结合使用。
const newChecked = ["recreational","charity"]
const allActivities = [
{activity: '...',type: 'social',},{activity: '...',type: 'charity',type: 'recreational',];
const res = allActivities.filter(({type})=>!newChecked.includes(type));
console.log(res);您可以使用 Array.prototype.reduce 函数创建一个新数组
const newChecked = ["recreational","charity"]
const allActivities = [
{activity: '...',];
const newActivitiesList = allActivities.reduce((accumulator,current) => {
if(newChecked.indexOf(current.type) === -1) {
return accumulator.concat(current);
} else {
return accumulator;
}
},[]);
console.log(newActivitiesList);