使用内生回归变量进行分位数回归以获取面板数据

我正在使用分位数回归方法来估计面板数据模型,该模型使用Harding和Lamarche的工具变量,R in Economics Letters 104(2009),133-135:

n <- 10                                      # number of cross sectional units
m <- 25                                      # number of time series units
rdu = 0.5                                    # correlation parameter
tau = 0.5                                    # quantile of interest
s <- rep(1:n,each=m)                         # strata 
Z <- model.matrix(s~as.factor(s)-1)[,-1]     # incidence matrix 
set.seed(25)
mu <- rep(rchisq(n,3),each=m)
epsilon <- rchisq(length(s),3)
XZ <- cbind(mu + epsilon,Z)
iv <- rep(rnorm(n),each=m) + rnorm(length(s))
ief <- rep(rnorm(n),each=m)
v <- rep(rnorm(n),each=m) + rnorm(length(s))
u <- v*rdu + rnorm(length(s))*sqrt(1-rdu^2)
d <- iv + v
y <- ief + u
rq.fit.ivpanel(d,XZ[,1],iv,y,s,tau=tau) -> bhat
round(bhat,3)
rq.se.ivpanel(bhat,d,tau=tau) -> bsehat
round(bsehat,3) -> bsehat
colnames(bsehat) <- c("endog","exog",rep("ie",n-1),"int")
rownames(bsehat) <- c("beta","se")
bsehat

作为R的初学者,我确实发现将代码(上面提到的)应用于我的数据有些困难。 该代码可以很好地处理R生成的随机数据,但是我真的不知道如何使其适用于我的Excel数据(其中包含“ Y”作为因变量,“ X1”作为自变量(假定是内生的),自变量“ X2”,“ X3”(假定是外生的)。

以下代码用于从Harding and Lamarche(2009)here

中生成rq.fit.ivpanelrq.se.ivpanel函数
#############################################
# Quantile Regression IV Panel Data Functions
# Harding and Lamarche,Economics Letters 104 (2009),133-135 
##########################################################################
# Functions
##########################################################################
rq.fit.fe <- function(X,w=1,taus=tau){
require(SparseM)
require(quantreg)
K <- length(w)
if(K != length(taus))
stop("length of w and taus must match")
X <- as.matrix(X)
p <- ncol(X)
n <- length(levels(as.factor(s)))
N <- length(y)
if( N != nrow(X))
 stop("dimensions of y,X must match")
D <- cbind(as(w,"matrix.diag.csr") %x% X)
y <- c(w %x% y)
a <- c((w*(1-taus)) %x% (t(X)%*%rep(1,N)))
rq.fit.sfn(D,rhs=a)}
#############################################
rq.fit.ivpanel <- function(d,exo,tau){
# IV Quantile Regression with Fixed Effects
# s is an strata indicator
# d is the endogenous variable
# exo are the exogenous variables,no intercept.
# iv is the intrument
Z <- model.matrix(s~as.factor(s)-1)[,-1]
exo <- cbind(exo,Z)
X <- cbind(exo,1)
x <- cbind(d,X)
w <- cbind(iv,X)
ww <- t(w) %*% w
ww.inv <- ginv(as.matrix(ww))
wd <- t(w)%*%d
dhat <- w%*%ww.inv%*%wd
PSI <- cbind(dhat,X)
PSI1 <- cbind(d,X)
coef <- rq.fit.fe(PSI,tau=tau)$coef
resid <- y - PSI1%*%coef
mu1 <- mean(resid)
sigma1 <- var(resid)
c <- ((1-tau)*tau)/(dnorm(qnorm(tau,mu1,sqrt(sigma1)),sqrt(sigma1))^2)
PSIinv <- diag(length(coef))
PSIinv <- backsolve(qr(x)$qr[1:length(coef),1:length(coef)],PSIinv)
PSIinv <- PSIinv %*% t(PSIinv)
vc1 <- c*PSIinv
std <- sqrt((length(y)/100)*diag(vc1))
alpha <- seq(coef[1]-2*std[1],coef[1]+2*std[1],by=std[1]/20)
z <- cbind(dhat,X)
betas <- matrix(NA,dim(z)[2],length(alpha))
g <- matrix(NA,length(alpha),1)
for (i in 1:length(alpha)){
ya <- y - alpha[i]*d
betas[,i] <- rq.fit.fe(z,ya,tau=tau)$coef
g[i,] <- max(svd(betas[1:dim(dhat)[2],i])$d)}
I <- which.min(g[,1])
param1 <- alpha[I]
est1 <- betas[(dim(dhat)[2]+1):dim(z)[2],I]
c(param1,est1)}
#############################################
rq.se.ivpanel <- function(bhat,tau){
n=length(y)
Z <- model.matrix(s~as.factor(s)-1)[,-1]
X <- cbind(exo,Z,1)
S0 <- cbind(iv,X)
D <- cbind(d,X)
k=dim(D)[2]
vc <- matrix(0,k,k)
S <- (1/n)*t(S0)%*%S0
resid <- y - D%*%bhat
h <- c(1.364 * ((2*sqrt(pi))^(-1/5))*sqrt(var(resid))*(n^(-1/5)))
J = (1/(n*h))*t(c(dnorm(resid/h)) %o% c(rep(1,dim(D)[2])) * D)%*%S0
vc = (1/n)*(tau-tau^2)*ginv(as.matrix(J))%*%S%*%ginv(as.matrix(J))
rbind(bhat,(sqrt(diag(vc))))}
huangzhu_QQ 回答:使用内生回归变量进行分位数回归以获取面板数据

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